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X^2-19X+19=0
a = 1; b = -19; c = +19;
Δ = b2-4ac
Δ = -192-4·1·19
Δ = 285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{285}}{2*1}=\frac{19-\sqrt{285}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{285}}{2*1}=\frac{19+\sqrt{285}}{2} $
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